Rays PQ and QR are perpendicular. p;oint S lies in the interior of angle PQR. If angle PQS equals 4+7a and angle SQR equals 9+4a, find the angle PQS and angle SQR. Can you please help me, I don't understand it.
In triangle ABC, X and Y are the midpoints of BC and AC, respectively. The perpendicular bisectors of BC and AC intersect at a point O inside the triangle. If angle C = 47 degrees, then find the measure of angle XOY?