A 23 kg suitcase is being pulled by a handle that is at an angle of 22 degrees above the horizontal. If the normal force exerted on the suitcase is 185 N, what is the force applied to the handle?

*** Objects NOT on an incline they are being pushed/pulled at an angle along a horizontal surface.

Information you have:

m=23kg
Fg(1)=185N
Using the Fg=mg, you can figure out the force exerted on the suitcase by gravity if there was no force pulling it:
Fg=mg
Fg=(23kg)(8=9.81m/s^2)
Fg=225.63N
Fg-Fg(1)=F experienced by handle
225.63N-185N=40.63N

To determine the force applied to the handle, we need to break down the weight of the suitcase into horizontal and vertical components. The vertical component will be balanced by the normal force exerted on the suitcase, while the horizontal component will be the force applied to the handle.

Step 1: Find the weight of the suitcase
The weight of the suitcase can be calculated using the formula: Weight = mass × acceleration due to gravity.
Weight = 23 kg × 9.8 m/s^2
Weight = 225.4 N

Step 2: Find the vertical component of the weight
The vertical component can be found using trigonometry. Since the handle is at an angle of 22 degrees above the horizontal, the vertical component is given by: Vertical component = Weight × sin(angle).
Vertical component = 225.4 N × sin(22 degrees)
Vertical component ≈ 82.09 N

Step 3: Find the force applied to the handle
The force applied to the handle is the horizontal component of the weight, which can be calculated using: Force applied to handle = Weight × cos(angle).
Force applied to handle = 225.4 N × cos(22 degrees)
Force applied to handle ≈ 205.57 N

Therefore, the force applied to the handle is approximately 205.57 N.

To find the force applied to the handle, we can break down the forces acting on the suitcase into its vertical and horizontal components.

1. Vertical Component:
The normal force exerted on the suitcase, which acts perpendicular to the surface, is equal to the weight of the suitcase. Therefore, the weight of the suitcase can be calculated as:
Weight = mass x acceleration due to gravity
Weight = 23 kg x 9.8 m/s^2
Weight = 225.4 N

Since the suitcase is on a horizontal surface, the normal force is equal to the weight of the suitcase. Thus, the normal force is 185 N.

The force acting in the vertical direction is the vertical component of the force applied to the handle, which we will denote as Fy. Since the handle is at an angle of 22 degrees above the horizontal, we can find the vertical component using trigonometry:
Fy = Force applied to the handle x sin(angle)
185 N = Force applied to the handle x sin(22 degrees)

Now we can solve for the force applied to the handle:

Force applied to the handle = 185 N / sin(22 degrees)
Force applied to the handle ≈ 555.98 N (rounded to the nearest whole number)