Math
posted by Shawn .
What is the probability that a number chosen at random from the range 1,000,000,000 to 9,999,999,999 inclusive will contain ten different digits? Round your answer to the nearest millionth

The number of ways the 10 distinct digits can form distinct numbers is given by
10!.
So the probability is 10! divided by the number of possible outcomes. 
The first digit on the right can be any number from 0 to 9 so ten choices
1/10 so far
the second digit (tens place) can be one of 9
1/10 * 1/9
the third can be one of 8 remaining
1/10 * 1/9 * 1/8
etc
get the picture? 
So after i do all that should i get one whole number

No, you will not get a whole number
a probability is a number between 0 and 1
1/10! which is about .00000027
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