posted by alison .
you are designing a 1000-cm^3 right circular cylindrical can whose manufacture will take waste into account. There is no waste in cutting the aluminum for the side, but the top and bottom of radius r will be cut from squares that measure 2r units on a side. The total amount of aluminum used up by the can will therefore be: A=8r^2 +2(pi)(r)(h)
What is the ratio of h to r for the most economical can?
Never mind... I got the answer!