Physics
posted by Ray .
A block of wood with volume V floats in water with 0.68V submerged. In oil the block floats with 0.86V of its volume submerged.
What's the density of the wood?

All you need to answer that is the amount submerged in water, and the density of water.
According to Archimedes Principle:
(Water density) * 0.68 V
= (wood density)* V
Cancel out the V and use the density of water
1.00 g/cm^3 * 0.68 = wood density 
so you are telling that .68V = (Wood density)*V.....What if .40V(say) is submerged, then will it be .40V = (Wood density)*V ????......Ur theory is wrong.....
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