posted by alex .
you have 40 coins, quarters dimes and nickles and they equal $6.00. you have two more quarters then nickles. how many of each do you have
let the number of nickels be x (nickels, not nickles)
then the number of quarters is x+2
then the number of dimes is 40 - x - (x+2)
5x + 25(x+2) + 10(38-2x) = 600
Let q = number of quarters
let d = number of dimes
let n = number of nickels.
q + d + n = 40
0.25q + 0.10d + 0.05n = 6.00
q = n+2
Solve for the three unknowns. Check my thinking.