math... precalculus
posted by alexa .
how do i solve this equation?
log3x+log3(x24)=4

I will assume you mean log_{3} for all
log3x+log3(x24)=4
log_{3} (x/(x24)) = 4
3^4 = x/(x24)
81 = x/(x24)
81x  1944 = x
x = 24.3
Respond to this Question
Similar Questions

Math
(I have two questions) 1. Solve for x without a calculator: log3(x^2)=2log3(4)4log3(5) This is what I have so far: 2log3(x)=log3(4^2)log3(5^4) 2log3(x)=log3(16/625) ...and now I'm stuck. 2. Simplify: 2log4(9)2log3 <how do you … 
Precalculus
Please help me with these questions ASAP!! Suppose that f(x)=log3(x1) a)If f(6)=1.4 and f(8)=1.7,then evaluate log3(35) and log3(7/5). b)If f(3)=0.6, find log9(2). 
PreCal
1) Solve the equation exactly for x: log3 x  log3(x3) = 2 I got 1 as an answer. Is this correct? 
math (precalc)
Solve for x: 1. 3^2x+3^x+14=0 2. log3(x=12)+log3(x+4)=2 3. lnx+ln(x+2)=4 4. 3*4^x+4*2^x+8=0 
Math
Solve for x. log3(x+7)=2log3(x1) Write the exact answer using base10 logarithms. 
Algebra
Solve the equation. 2log3 y = log3 4+ log3 (y+8) Here's what ive got take out the logs and say y^2= 4+ y +8 which simplifies to (y^2)y=12 how do i simplfy the y? 
Math
Solve the logarithmic equation. Express your solutions in exact form only. Please show all of your work. log3(x+2) + log3(x+8) – 2 = log3(x+3) 
math
Solve for x in the following equations. (4 marks) log3(x  5) + log3(x + 3) = 2 < both log3.. 3 is subscript log7x + log7(x  1) = log72x < all log7.. 7 is subscript. 
Algebra (logs)
Please help, I need help on these two problems. Solve the equation. log3(x − 16) = log3(9x) e^1 + ln(7) It appears on the homework that the ln(7) is written like this ^ln(7) but I am still stuck on it. Thanks! 
MATH Precalculus
Use the Laws of logarithms to rewrite the expression log3(x^18*sqrt3(y12)) in a form with no logarithm of a product, quotient or power. After rewriting we have log3(x^18*sqrt3(y12))=Alog3(x)+Blog3(y) With the constant A=?