Post a New Question

Calculus

posted by .

Find the first and second derivatives of the given functions.

y=¡î(x©÷+1)
y'=x(x©÷+1)^(-1/2)
y"=[1(x©÷+1)^(-1/2)]-[(1/2)[(x©÷+1)^(-3/2)](2x)(x)]
y"=[(x©÷+1)^(-1/2)]-[(x©÷)(x©÷+1)^(-3/2)]

Is the second derivative right?

  • Calculus -

    y=root(x^2+1)
    y'=x(x^2+1)^(-1/2)
    y"=[1(x^2+1)^(-1/2)]-[(1/2)[(x^2+1)^(-3/2)](2x)(x)]
    y"=[(x^2+1)^(-1/2)]-[(x^2)(x^2+1)^(-3/2)]

  • Calculus -

    I agree

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question