Post a New Question

algebra

posted by .

A wholesaler mixed coffee beans worth $6/kg with another kind worth $8.80/kg. The 16kg mixture was worth $6.70/kg. How many kilograms of each type was used?

  • algebra -

    Let the amount of the $6 mixture used be x kg
    let the amount of the $8.80 mixture be 16-x kg

    then
    6x + 8.8(16-x) = 6.7(16)

    solve for x

  • algebra -

    thnx SO MUCH

  • algebra -

    6x+1408-88x=1072
    you may move the decimal 1 place if you want
    1408-82x=1072
    1408-1072=82x
    336=88x
    x=336/88

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question