calc
posted by casey .
Let g(s)=1/(s2)on the interval (0,1). Find the absolute maximum and absolute minimum of g(s) on this interval

g'(s) = 1/(s2)^2
setting this equal to zero has no solution, so the function has no max/min
and since g'(s) is always negative, the function is decreasing for all values of s except s = 2
so let's look at the endpoints of the interval
g(0) = 1/2 =  1/2
g(1) = 1/1 = 1
so for the given interval, the max is 1/2 and the min is 1