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Let g(s)=1/(s-2)on the interval (0,1). Find the absolute maximum and absolute minimum of g(s) on this interval

  • calc -

    g'(s) = -1/(s-2)^2
    setting this equal to zero has no solution, so the function has no max/min
    and since g'(s) is always negative, the function is decreasing for all values of s except s = 2

    so let's look at the endpoints of the interval
    g(0) = 1/-2 = - 1/2
    g(1) = 1/-1 = -1

    so for the given interval, the max is -1/2 and the min is -1

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