posted by Anonymous .
In a family with two children, what are the probabilities of the following outcomes, assuming that the birth of boys and girls is equally likely? a. Both are boys.b. The first is a girl and the second a boy. c. Neither is a girl. d. At least one is a girl.
I am questioning myself because this seems too easy. The answer would be D, right?
If the chances are equally likely, then the outcome of two children would be one boy and one girl, correct?
I am supposed to figure out the probabilities of each statement...does anyone know how to do that?
In the question you are dealing with a 1/2 probability rate, so in
a-it wouls be 2 of the 1/2 rates which is 25%
b-it would be the same b/c its still two 1/2 senerios, so 25% again
c-same thing 25%
d-this is a 75% chance b/c the secod child is still an unknown factor and could be either a girl or boy
Thank you so much. I understood there was a 50% chance of a boy and a 50% chance of a girl, I just didn't know how to equate the probabilities.