Chad was the same age as Shelly, and Holly was 4 years older than both of them. Chad's dad was 20 when Chad was born, and the average age of the four of them is 39. How old is Chad?
try 2x+(x+4)+(x+20)=39. Solve for x and it should give you chads age
To solve this problem, let's break down the given information step by step:
1. Chad was the same age as Shelly: This means Chad's age is equal to Shelly's age. Let's call their age x.
2. Holly was 4 years older than both of them: Since Chad and Shelly's age is x, then Holly's age will be x + 4.
3. Chad's dad was 20 when Chad was born: This implies that there is a 20-year age gap between Chad and his dad.
Now, let's calculate the average age of the four individuals:
Average age = (Chad's age + Shelly's age + Holly's age + Chad's dad's age) / 4
39 = (x + x + (x + 4) + (x + 20)) / 4
To solve this equation, we'll follow these steps:
1. Combine like terms:
39 = (4x + 24) / 4
2. Multiply both sides of the equation by 4 to eliminate the fraction:
4 * 39 = 4x + 24
3. Simplify:
156 = 4x + 24
4. Subtract 24 from both sides of the equation:
156 - 24 = 4x
132 = 4x
5. Divide both sides of the equation by 4:
132 / 4 = 4x / 4
33 = x
Therefore, Chad's age (and Shelly's age) is 33 years old.