PHYSICS
posted by Sasha .
a child sitting 1.10 m from the center of a merry go round moves with a speed of 1.25 m/s. calculate the centripetal acceleration of the child and the net horizontal force exerted on the child (mass = 25 kg).

PHYSICS 
drwls
The centripetal acceleration is
a = V^2/R and the force is
F = m a = m V^2/R.
m = 25 kg
V = 1.25 m/s
R = 1.10 m
Do the numbers. 
PHYSICS 
Sasha
so i did a = 1.25^/1.1 = 1.42 m/s^2
then F =ma = 25(1.42) = 35.5N is that right? 
PHYSICS 
Maggie
My question was that the child was 22.5 kg and 1.20 m away from the center and the speed was 1.30 m/s. For a I got 1.30^2/1.20 = .49 m/s^2 and for Force I got 22.5*.49 =11.03 N.
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