Dr.Bob222,

I've been attempting the problem I posted previously about the ferrous ammonium sulphate, but I'm having no luck. I'm having trouble with my balanced equation. Do you mind showing me how to do the balanced equation?
Thank you

You didn't provide enough information in your previous post to write a balanced equation which is why I wrote the solution in generic terms instead of specific terms. The post simply states that excess oxalate was used........and the iron complex. Please provide details on how the complex was prepared.

Of course, I'll be happy to help you with balancing the equation for the reaction involving ferrous ammonium sulfate. In order to balance the equation, you need to ensure that the number of atoms on both sides of the equation is equal.

Let's start by writing down the unbalanced equation for the reaction:

Fe(NH4)2(SO4)2 + KMnO4 + H2SO4 → Fe2(SO4)3 + MnSO4 + K2SO4 + NH4HSO4 + H2O

First, we can focus on balancing the atoms that appear in only one compound on each side of the equation. In this case, we can start by balancing the manganese (Mn) atom. There is one Mn atom on the left side and one on the right, so we can leave Mn as it is for now.

Next, let's balance the sulfur (S) atoms. There are two sulfate (SO4) ions on the left side but three on the right side. To balance the sulfurs, we need to multiply the sulfate ion (SO4) on the left side by 3:

Fe(NH4)2(SO4)2 + KMnO4 + H2SO4 → Fe2(SO4)3 + MnSO4 + K2SO4 + NH4HSO4 + H2O

We have balanced the sulfurs, but now we see that there are too many oxygen (O) atoms on the right side of the equation compared to the left side. To balance the oxygens, we need to add water (H2O) on the left side of the equation. We will use the coefficients to balance the oxygen atoms:

Fe(NH4)2(SO4)2 + KMnO4 + H2SO4 → Fe2(SO4)3 + MnSO4 + K2SO4 + NH4HSO4 + 4H2O

Now, let's balance the hydrogen (H) atoms. There are eight hydrogen atoms on the right side but only two on the left side. To balance the hydrogens, we need to add sulfuric acid (H2SO4) to the left side of the equation:

Fe(NH4)2(SO4)2 + KMnO4 + 8H2SO4 → Fe2(SO4)3 + MnSO4 + K2SO4 + NH4HSO4 + 4H2O

Lastly, let's balance the iron (Fe) atoms. There is one Fe atom on the left side and two on the right side. To balance the irons, we need to multiply Fe(NH4)2(SO4)2 on the left side by 2:

2Fe(NH4)2(SO4)2 + KMnO4 + 8H2SO4 → Fe2(SO4)3 + MnSO4 + K2SO4 + NH4HSO4 + 4H2O

Now, the equation is balanced, and we have:

2Fe(NH4)2(SO4)2 + KMnO4 + 8H2SO4 → Fe2(SO4)3 + MnSO4 + K2SO4 + NH4HSO4 + 4H2O

Make sure to always double-check your balanced equation to ensure that the number of atoms on both sides is equal.