A flashlight that is powered by 12 Volts and uses a bulb with a resistance of 90 Omega will have a current _________________ Amps.
To calculate the current (I) in a circuit, you can use Ohm's Law, which states that the current flowing through a resistor is equal to the voltage across the resistor divided by the resistance.
Ohm's Law: I = V / R
In this case, the voltage (V) is given as 12 Volts, and the resistance (R) of the bulb is given as 90 Ω.
Substituting the values into the formula: I = 12V / 90Ω
Now, let's calculate the value:
I = 0.133 Amps (rounded to three decimal places)
Therefore, the current flowing through the bulb will be approximately 0.133 Amps.