Algebra
posted by Josie .
I need help solving these three problems.
1/4(7 + 3g) + g/8
Twice the greater of two consecutive odd integers is 13 less than three times the lesser number. Find the integers.
About 4.9 million households had one brand of personal computers in 2001. The use of these computers grew at an average rate of 0.275 million households a year. In 2001, about 2.5 million households used another type of computer. The use of these computers gew at an average rate of 0.7 million households a year. How long will it take for the two types of computers to be in the same number of households?
Thanks.

For the first one, are you simplifying?
1/4(7 + 3g) + g/8
= (7+3g)/4  g/8
= (14 + 6g)/8  g/8
= (14 + 5g)/8
For the second, solve
2(x+2) = 3x  17
For the third, let t=0 correspond with the year 2001
so C1 = .275t + 4.9
and C2 = .7t + 2.5
Now equate C1 and C2
.275t+4.9 = .7t+2.5
275t + 4900 = 700t + 2500
2400 = 425t
t = 5.6 yrs.
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