calculus

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f(x) = (3x^2) (csc4x)^4 // f'(x)=?
my notes say : f'(x) = (3x^2)5(csc4x)^4(-csc(4x)(tan4x)(4)+(csc4x)^5(6)
I redid it and i got : f'(x) = (3x^2)5(csc4x)^4(-csc4x)(cot4x)(4) + (csc4x)^5(6x)
which is correct? if its my notes why?

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