chemistry

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how would you prepare a 500 mL of 0.020M KMnO4 solution?

  • chemistry -

    molarity = # moles/liter of solution.
    So how many moles do we want for 500 mL of 0.02 M KMnO4? We want
    M x L = moles = 0.02 x 0.5 L = 0.01 moles.
    moles = grams/molar mass.
    You know moles and molar mass, calculate grams.

  • chemistry -

    1.5803

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