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A student was asked to make some copper(II) sulfate-5-5 (CuSO4.5(H2O) BY reacting copper(II) oxide (CuO) with sulfuric acid.
a) Calculate the molar mass of the copper (II) sulfate-5-water
which is (64+32+64) + (10+80)=250 mol

b)Calculate the amount (in mol) of copper (II) sulfate-5-water in a 10,0g sample?

C) Calculate the mass of copper (II) oxide needed to make the 10,0g sample?

Can anyone help me with question b,c??

  • chemistry. -

    Amount of moles= mass/molar mass
    No. of moles= 10.0g/250 g
    No. of moles= 0.04 moles

    c) CuO + H2SO4 ----> CuSO4 + H2O
    mol 1 1 1 1

    1 mole of CuO = 1 mole of CuSO4.5H2O
    CuO= 64g + 16g= 80g

    80 g of CuO = 250 g of CuSO4
    x = 10g of CuSO4

    10g x 80g/250g
    =3.2 grams of CuO

  • chemistry. -

    thanks you very much.

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