Algebra 2 URGENT
posted by Trisan .
Sally invested a total of $4500, some at 9% per year and the rest at 6% per year. The return from the 9% investment exceeds that from the 6% investment by $180. How much did she invest at each rate?

I can't tell you how to set it up but I can tell you that she invested $3000 at 9% and $1500 at 6%.
3000 x .09 = 270
1500 x .06 = 90
270  90 = 180 
let the amount invested at 9% be x
then the amount invested at 6% is 4500x
.09x + .06(4500x) = 180
solve for x
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