calculus

posted by .

how do not understand how to find a deriviative of this function?Do i use chain rule and product rule?

r= the square root of (theta*sin*theta)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Calculus

    Below are the 5 problems which I had trouble in. I can't seem to get the answer in the back of the book. Thanks for the help! lim (theta-pi/2)sec(theta) theta->pi/2 Answer: -1 I am not sure what to do here. lim (tan(theta))^(theta) …
  2. Calculus

    How do I use the chain rule to find the derivative of square root(1-x^2) also, are there any general hints or tips for determining when the chain rule and product or quotient rule should be used?
  3. Calculus

    I wanted to confirm that I solved these problems correctly (we had to convert the polar curves to Cartesian equations). 1.rcos(theta)=1 x=1 2.r=2*sin(theta)+2*cos(theta) r^2=2rsin(theta)+2rcos(theta) x^2+y^2=2y+2x (a little unsure …
  4. Trigonometry

    I don't understand how I'm supposed set the problem up or what theta is... Use the given function value(s), and trigonometric identities (including the cofunction identities), to find the indicated trigonometric functions. sec theta …
  5. math

    how do i solve this? do i have to use both chain and product rule- how do i do that?
  6. calculus

    how do not understand how to find a deriviative of this function?
  7. Algebra II

    Multiple Choice (theta) means the symbol 0 with the dash in it. 1.)Which expression is equivalent to tan(theta)-(sec(theta))/(sin(theta))?
  8. Calculus Help

    find dy/d(theta) theta=2 , if y=sin(pi/(square root(theta^2+5))) Show steps thanks!!!
  9. Math (Calculus)

    Hello, Could somebody please help me with the following question?
  10. Algebra2

    The function f(theta) and g (theta) are sine functions where f(0)=g(0)=0. The amplitude of f (theta) is twice the amplitude of g(theta). The period of f(theta) is one-half the period of g(theta). If g (theta) has a period of 2pi and …

More Similar Questions