the speed of train A is 16 mph slower than the speed of train B. Train A travels 210 miles in the same time it takes train B to travel 290 miles. Find the speed of each train.
Train A = 58 mph
Train B = 74 mph
Can you tell me if this is right
You could have tested your answers to realize you were wrong.
210/58 = 3.62
290/74 = 3.9
I got
Train A 42 mph
Train B 58 mph
test
210/42 = 5
290/58 = 5
Thank you I forgo about checking the answer
Yes, your answer is correct. Train A travels 210 miles in the same time it takes Train B to travel 290 miles. Let's solve this problem step by step to explain it in detail.
Let the speed of Train B be 'x' mph. According to the problem, Train A is 16 mph slower than Train B, so the speed of Train A is 'x - 16' mph.
To find the time taken by both trains, we can use the formula: time = distance / speed.
For Train A: time taken = 210 miles / (x - 16) mph
For Train B: time taken = 290 miles / x mph
As per the problem, both trains take the same time:
210 miles / (x - 16) mph = 290 miles / x mph
To solve this equation, we can cross multiply:
210x = 290(x - 16)
Solving this equation step by step:
210x = 290x - 4640
Combining like terms:
290x - 210x = 4640
80x = 4640
Dividing both sides by 80:
x = 58
So, the speed of Train B, denoted by 'x', is 58 mph.
The speed of Train A is 16 mph less than Train B, so the speed of Train A is (58 - 16) mph = 42 mph.
Therefore, Train A has a speed of 42 mph, and Train B has a speed of 58 mph. So your answer is correct.