# Physics

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Assume it takes 6.00 minutes to fill a 45.0 gal gasoline tank. (1 U.S. gal = 231 in.3)

I don't know how to solve for part C.

(a) Calculate the rate at which the tank is filled in gallons per second.

(b) Calculate the rate at which the tank is filled in cubic meters per second.

(c) Determine the time interval, in hours, required to fill a 1 m3 volume at the same rate.

• Physics -

??m3/sec x sec = m3
Solve for sec.

Then convert sec to hours.
sec x (1 min/60 sec) x (1 hr/60 min) = ??

• Physics -

??m3/sec x sec = m3
Solve for sec.

Then convert sec to hours.
sec x (1 min/60 sec) x (1 hr/60 min) = ??

---------------

So I have the rate 4.73e-4 m3/s. I'm not sure how the cancellation for the m3 to disappear, but I get the converting the second to hours part, just not the step prior to get there?

• Physics -

rate = meter*meter*meter/seconds x seconds = meter*meter*meter. The second in the denominator of the first part cancels with second in the numerator of the second part. This is just like
(meter/second) x second = meter

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