Physics

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At what altitude above the Earth's surface would your weight be three-fourths of what it is at the Earth's surface? Assume re = 6.371 10^3 km.

  • Physics -

    Based on Newton's law of universal gravitation,
    F=GMm/r²
    which means that the weight would be inversely proportional to the square of the distance from the centre of the Earth.
    If H is the altitude when the weight becomes 3/4 of what's on the surface, then
    (re/(re+H))^2=3/4
    Solve for H.

  • Physics -

    Solved out for H:

    (6371/sqrt(3/4)) - 6371 = H

    for other fractions just plug in where 3/4's is.

    Hope this helps!

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