chemistry.

posted by .

The relative mass of aluminum chloride is 267 and its composition by mass is 20,3% Al and 79,7% chlorine. Determine the empirical and molecular formulas of Aluminum chloride.

  • chemistry. -

    Take a 100 g sample.
    This will give you 20.3 g Al and 79.7 g Cl. Convert each of these grams into moles.
    moles Al = 20.3/atomic mass Al
    moles Cl = 79.7/atomic mass Cl.

    Now find the ratio, in small whole numbers, to equate the two. The easiest way to do that is to divide the smaller number by itself (which assure you it will be 1.000), then divide the other number by the same small number. You should get AlxCly where x and y are small whole numbers. That will give you the empirical formula.
    Then add up the atomic masses to find the mass of the empirical formula, divide into 267 to determine n, round n to a whole number, and multiply by the empirical formula to find the molecular formula. The molecular formula will be (AlxCly)n.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. CHEM

    Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s) + 3Cl2(g) -> 2AlCl3(s) You are given 19.0g of aluminum and 24.0g of chlorine gas. a)If you had excess chlorine, how many moles of of …
  2. CHEM-last part prob.

    Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s) + 3Cl2(g) -> 2AlCl3(s) You are given 19.0g of aluminum and 24.0g of chlorine gas. a)If you had excess chlorine, how many moles of of …
  3. chemistry

    Aluminum nitrate and ammonium chloride react to form alluminum chloride, nitrogen, and water. what mass of aluminum chloride is present after 43.0 g of aluminum nitrate and 43.0 g ammonium chloride have reacted completely?
  4. Chemistry

    Aluminum and chlorine gas react together to make Aluminum chloride. What is the limiting reactant if 20.0g of Al and 30.0g of Cl2 are used?
  5. Chemistry

    Knowing that 2 aluminum atoms and 3 chlorine molecules react to produce 2 units of aluminum chloride, how many moles of aluminum chloride can be produced by reacting 7.8 moles of chlorine with excess aluminum?
  6. Chemistry

    1) A compound has the following percentages by mass: barium, 58.84%; sulfur, 13.74%; oxygen, 27.43%. Determine the empirical formula of the compound. 2) If a 1.271-g sample of aluminum metal is heated on a chlorine gas atmosphere, …
  7. chemistry

    3. Find the empirical formula for a compound that consists of aluminum and chlorine in which the aluminum is 20.2 % by mass. 4. A sample contains 71.65% CL, 24.27% C nad 4.07% H. the molecular weight is known to be 98.96 g/mol. What …
  8. chemistry

    A 12.0g sample of carbohydrate contain 4.50g of carbon, 3.25g of oxygen, and some hydrogen. Determine the percent by mass of hydrogen in your product. Find the empirical formula for a compound that consists of aluminum and chlorine …
  9. Chemistry 1300

    1) Aluminum metal reacts with chlorine gas to form solid aluminum trichloride, AlCl3. What mass of chlorine gas (Cl2) is needed to react completely with 163 g of aluminum?
  10. Chemistry

    Which of the following are true about the use of aluminum chloride in the Friedel-Crafts acylation reaction?

More Similar Questions