Algebra 1
posted by Elisa .
Write the equation in standard form for the line that passes through (6, 1) and (10,*)
So far I have 81 is 9 and 106 is 4, is the 9 correct?
Then y plus 10 equals 9/4(x  8)
Then multiply by 2 so 2y plus 20 equals 18/4x  146/4
Is this correct so far?

I replied to one of your previous questions which is almost identical to this one, but apparently you did not look at it.
http://www.jiskha.com/display.cgi?id=1254199568
anyway...
first of all, you have an error in your calculation of slope.
slope = (8  (1))/(10  6)
= 7/4
then, using (10,8)
y  (8) = (7/4)(x10)
y + 8 = (7/4)(x10)
multiply both sides by 4 to get rid of fractions...
4y + 32 = 7(x10)
4y + 32 = 7x + 70
7x + 4y = 38
I usually check using the point NOT used to find the equation, the (6,1)
Left Side = 7(6) + 4(1)
= 42  4
= 38
= Right Side !
You are making errors in subtracting integers. 
yes, I did see the reply earlier. However, I'm still having trouble figuring out how to do the work.
thanks for your help.