Algebra 1

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Write the equation in standard form for the line that passes through (6, -1) and (10,-*)

So far I have -8-1 is -9 and 10-6 is 4, is the -9 correct?

Then y plus 10 equals 9/4(x - 8)
Then multiply by 2 so 2y plus 20 equals 18/4x - 146/4

Is this correct so far?

  • Algebra 1 -

    I replied to one of your previous questions which is almost identical to this one, but apparently you did not look at it.
    http://www.jiskha.com/display.cgi?id=1254199568

    anyway...
    first of all, you have an error in your calculation of slope.

    slope = (-8 - (-1))/(10 - 6)
    = -7/4

    then, using (10,-8)
    y - (-8) = (-7/4)(x-10)
    y + 8 = (-7/4)(x-10)
    multiply both sides by 4 to get rid of fractions...
    4y + 32 = -7(x-10)
    4y + 32 = -7x + 70
    7x + 4y = 38

    I usually check using the point NOT used to find the equation, the (6,-1)

    Left Side = 7(6) + 4(-1)
    = 42 - 4
    = 38
    = Right Side !

    You are making errors in subtracting integers.

  • Algebra 1 -

    yes, I did see the reply earlier. However, I'm still having trouble figuring out how to do the work.

    thanks for your help.

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