Algebra 2
posted by newt .
1. Plane A is 40 mi south and 100 mi east of Plane B. Plane A is flying 2 miles west for every mile it flies north, while Plane B is flying 3 mi east for every mile it flies south.
a. Where do their paths cross?
b. Which plane must fly farther?
c. What ratio of the speed of Plane B to the speed of Plane A would
produce a midair collision?

Start by drawing a diagram of the situations, such as:
http://img101.imageshack.us/img101/3371/newt.jpg
a. The point where the two paths cross is at (40,20) relative to plane A. (Check my graphical solution).
b. not sure what exactly is requested.
Either plane A can fly further south, or plane B a little further north, or they can avoid each other by changing altitudes.
c. The deadly ratio can be found by calculating the distances of each plane from the intersection point (40,20). If the speeds are inversely proportional to the distance, it is likely to have a midair collision.
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