Post a New Question

Chemistry II

posted by .

Eugenol, the active ingredient in cloves, has a formula of C10H12O2. What is the boiling point of a solution containing 1.14g of eugenol dissolved in 10.0g of benzene? The boiling point of benzene is 80.1C and the boiling point elevation constant for benzene is 2.53C/m.

I got .0678mol for eugenol, is that correct?Do I use Delta T=(2.53C/m)(.0678mol)? I got a little confused.

  • Chemistry II -

    I don't get that.
    moles = grams/molar mass
    moles eugenol = 1.14/164.2 = 0.00694.

    molality = mols/kg solvent = 0.00694/0.010 = ?? (use m in the following).

    delta T = Kb*m
    delta T = 2.53*m

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question