posted by Mandy .
Eugenol, the active ingredient in cloves, has a formula of C10H12O2. What is the boiling point of a solution containing 1.14g of eugenol dissolved in 10.0g of benzene? The boiling point of benzene is 80.1C and the boiling point elevation constant for benzene is 2.53C/m.
I got .0678mol for eugenol, is that correct?Do I use Delta T=(2.53C/m)(.0678mol)? I got a little confused.
Chemistry II -
I don't get that.
moles = grams/molar mass
moles eugenol = 1.14/164.2 = 0.00694.
molality = mols/kg solvent = 0.00694/0.010 = ?? (use m in the following).
delta T = Kb*m
delta T = 2.53*m