Post a New Question

math (Algebra)

posted by .

Express x2+4x+7 in the form (x+p)2+q. Hence show that equation x2+4x+7=0 has no real root???...I have problem in writing square in my computer so remember x2 is x square and 2 after bracket is squarer too.

  • math (Algebra) -

    the usual way to write powers in this forum is x^2 for x2

    so x^2 + 4x + 7
    = x^2 + 4x + 4 - 4 + 7
    = (x+2)^2 + 3

    If I had the parabola y = (x+2)^2 + 3
    its vertex would be above the x-axis at (-2,3) and it opens upwards.

    So it cannot cross the x-axis.
    Since roots are simply the x-intercepts of the corresponding function, we conclude that there are no real roots.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question