?? Maths??

posted by .

Find the values of b and c for which x^2+bx+c is a factor of 2x^3-3x^2-3x-5

Ok, i've tried to find a factor of the quadratic function using trial and error.

Let f(x) = 2x^3-3x^2-3x-5
f(1) is not equals to 0
f(-1) is not equals to 0
and i cant find a number that would equate the function to 0. So i'm stuck and i don't know how i should go about doing this question. Help!

  • ?? Maths?? -

    Use long division: divide 2x^3-3x^2-3x-5 by x^2+bx+c

    You want the remainder to be 0, so you should be able to solve for b and c after you divide.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra 1.

    Factor: 50r^8 – 32r^2 The caret symbol represents a power. 2r^2(25r^6+16)= 2r 2 (25r 6 +16) DrBob222 forgot a minus sign: 50r^8 – 32r^2 = 2r^2(25r^6 - 16) Then, inside the brackets, you see a difference of two squares: 25r^6 - …
  2. math,algebra

    can someone help me i've tried different numbers but i can come out to factor this: 2b^2+6b-216=0 why don't you divide the equation by 2 to get b^2+3b-108=0 now by trial and error, can you find two factors of 108 that have a difference …
  3. Math

    How can I find the point of intersection of the graphs x^2=y=4 and 2x-y=1 by hand?
  4. Factor

    How do I factor these: 2x2 - 16x + 30 4x^2-9 x^2-5x 5x^2-26x+5 25x^2+4 Example: 2x^2 - 16x + 30 = 2 (x^2 - 8 x + 15) 2(x - 5)(x - 3) The first, factor out a 2 first. Then factor . The second...difference of two squares Third factor …
  5. math

    solve the equation x^3-5x^2-4x+20=0 I need a hint on how to solve this Look for the first root by graphical means or trial-and-error. Note that when x=2, x^3-5x^2-4x+20 = 8-20 -8 +20 = 0. Therefore 2 is one root and x-2 is a factor. …
  6. help with solving

    x^2+(x-2)^2 = (2x-6)^2 solve for x. thanks so much. Please keep in mind that tutors here won't simply do your work for you . I'm sure you'll get a better response if you show your work as far as you can get , so tutors will know where …
  7. Maths

    The question is "Show that z-2 is a factor of P(z)= z^3+mz^2+(3m-2)z-10m-4 for all values of m. For what values of m is (z-2)^2 a factor of P(z)?
  8. Pre Calculus

    using the factor theorem to show that x-c is a factor of P(X) for the given values of c, and factor 1. P(x)=x3-5x^2+8x-4; c=1
  9. Maths (factor theorem)

    9x^2 6xy 4y^2 is a factor of 27x^3 - 8y^3, find the other factor.
  10. Maths

    31+x+31-x-10=0 Solve x2/3+x1/3-12=0 If (x-3)is a factor of x2+4x-21=0,find the other factor (using long division)

More Similar Questions