Algebra
posted by Anonymous .
[2y^2+11y+5]/[4y^2+4y+1] / [2y^3+10y^2]/[4y^3]
=2y over (2y+1), right?

is this how you did it?
2Y^2+11Y+5/4Y^2+4Y+1 / 2Y^3+10Y^2= (Y+5)(Y+1)/(Y+1)(Y+1) / 2Y^2(Y+5)/4Y^3= 1/Y+1 / 4Y^3/2Y^2= 2Y OVER Y+1 
You didn't believe me ?
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