Algebra
posted by Anonymous .
x^225 over x^2+7x, divided by x^2+7x+10 over x^2+9x+14.
I found the solution to be x5 over x, is this correct?

yes,
don't forget the restrictions that
x cannot be equal to 2,5,7
(or else you divided by zero)
Respond to this Question
Similar Questions

algebra 1 help
6(32)^2 over 3^22(3)(2)+2^2 6(32)^2 over 3^22(3)(2)+2^2 6(5)^2 over 9+12+4 6(5)^2 over 3+4 6(25)^2 over 7 6x150 over 7 900 over 7 am i correct with this can i go any further . 6(32)^2 over 3^22(3)(2)+2^2 6(32)^2 … 
Algebra
I have to simplify these please help im not sure how things in parenthesis are exponets x(2)+8x12 over x2 2a(3)+a(2)3a over 6a(3)+5a(2)6a 3x(2)+2x1 over x(2)+3x+2 a(2)11a+30 over a(2)9a+18 2y(3)12y(2)+2y over y(2)6y+1 
Basic Math
Can somebody see if I did these right? 16 divided by (2)(4) over 2 to the third power plus 4= 16 divied by 8 over 6 + 4= 2/ 10 = 1/5. and 4  (3) + 1 over 22 divided by (2) = 4+3+1 over 22 divided by (2)= 8/3 = 2 2/3. Is what 
Basic Math
Can somebody see if I did these right? 16 divided by (2)(4) over 2 to the third power plus 4= 16 divied by 8 over 6 + 4= 2/ 10 = 1/5. and 4  (3) + 1 over 22 divided by (2) = 4+3+1 over 22 divided by (2)= 8/3 = 2 2/3. Is what 
finding midpoint
the midpoint formula is x1 + x2 divided by 2, y1 + y2 divided by two. if the coordinates are x1: a, y1:b and x2: c, y2: 0, what is the midpoint? 
Algebra
m+3 over 3m, divided by 6m over m+3 Would the solution be 1 over 18m? 
Algebra
x^3x^2y over x^2y^2, divided by x^3y over xy^2+y^3 My solution: y over x Am I right? 
ALGEBRA
If I am dividing the following: x^2+3x over x^2+2x3 by x over x+1.. i know to do the recip. of x over x+1 and get the foll. x^2 + 3x over x^2 + 2x 3 times x+1 over x... now (x^2+3x)(x+1) over (x^2+2x3)(x) now x(x+2)(x+1) x(x+2)(x1) … 
algebra
x over y minus y over x divided by 1 over y plus 1 over x. 
Algebra
Evaluate the express. nCr (9 over 6)(6 over 4)(3 over 1) n 9 6 3 r 6 4 1 I came up with, [10 over 6!(106] [6 over 4(42!) [3 over 1!(11)!] from there I so sorry I don't know where to go. thank you