Physics
posted by Willie .
A ball is tied to an elastic string of length 8.0 m and swung in a horizontal circle with a velocity of 0.8 m/s. When a metallic object is tied to a rope of length 2.75 m and swung in a horizontal circle, it makes one revolution in 2.9 s. The ratio of the centripetal force in the string to the centripetal force in the rope is 1/3.0. Find the mass of the metallic object attached to the rope, if the centripetal force in the string is 0.20 N.

Centripetal force on string, F1
= m1v²/r1
F1=0.2 N
Centripetal force on rope, F2
= m2r2ω²
Since 3F1=F2, therefore F2=0.6N
Equate F2=m2r2ω²
Since all variables are known except m2,
you can readily solve for m2. 
someone please answer this question

pllllllllllllllllleeeeeaaassssssse, unless im gonna fail my class

kidding, but someone answer this freakin question
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