posted by Pat .
Simplify the following
[2x / (3x (2nd power) - 5x - 2] + [(x-1) / (x (2nd power) -x - 20)]
let's write it this way
2x/(3x^2 - 5x - 2) + (x-1)/(x^2 -x - 20)
= 2x/[(3x+1)(x-2)] + (x-1)/[(x-5)(x+4)]
Your LCD is (3x+1)(x-2)(x-5)(x+4)
Unusual, as I had expected one of the factors to be the same in the denominators.
[2x(x-5)(x+4) + (x-1)3x+1)(x-2)]/[(3x+1)(x-2)(x-5)(x+4)]
expand the top and collect like terms.
Good luck, since the result will certainly not be more simplified than the original.