posted by Andy .
A Hollywood Daredevil plans to jump a canyon on a motorcycle. There is a 15 m drop and the horizontal distance originally planned was 60 m but it turns out the canyon is really 69.6 m across. If he desires a a 3.2 second flight time
I've figured out the upward motion part of the problem still having trouble with the downward motion (landing angle and final velocity). Can someone explain thanks a lot for all the help
I did the entire thing for you.
Vf is the vector addition of Vhoriz, Vvertical.
Vvertical= 15sinTheta - 4.9*3.2
Now the landing angle: Tan Thetaland=Vv/Vh and I just laid out those two for you.
Vlanding= sqrt(Vv^2 + Vh^2) or you can do it with trig.