# algebra

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Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 60 miles per hour. Train A passes a station at 8:25 p.m. If train B passes the same station at 8:37 p.m. at what time will train B catch up to train A?

• algebra -

Let the time between 8:25 and the moment they meet be t hours

So train B covers the distance from the station to where they meet in 12 minutes less than train A
and 12 minutes = 12/60 or .2 hours

then 60t = 40(t + .2)
solve for t, you should get t=.4hours
which is the same as .4(60) minutes or 24 minutes.

so they will meet at 8:49 pm

• correction -algebra -

I just looked at my definition of t again and according to my equation should have defined it as

Let the time between 8:37 and the moment they meet be t hours

I should then have added the 24 minutes to 8:37 to get a time of

9:01 pm

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