Calculus
posted by Stacy .
Find the average value of the function on the given interval:
f(x) = e^x/5, [0,5]

you are looking at dividing the definite integral of f(x) from 0 to 5 by the length of the interval, namely (50)=5.
∫(1/5)e^{x}dx
=(1/5)[e^{x}] from 0 to 5
=(1/5)(e^{5}e^{0})
=(1/5)(148.4131)
=29.483
The average over the interval
=29.483/5
=5.8965
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