# Chemistry II

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what is the molar mass of a gaseous organic compound with a density of 3.38 g/L at 40oC and a pressure of 1.97 atm?
I got 4.41M, is this correct?

• Chemistry II -

PV=nRT
PV=(g/M)RT-------M being molar mass, that is why g/M= amount of moles
MPV=gRT
M=(gRT)/ (PV)

Plug in all the values.

M= (3.38g x 0.0821 L atm x 313 K) / (1.97 atm x 1 L K) = 44 g

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