# Chemistry

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Use the following equation to answer the question...
4Fe(s)+3O2(g)---> 2Fe2O3(g)
Heat = -1700kJ

How many grams of rust form when 453kJ of energy is released?

• Chemistry -

1700 kJ are released when 2 moles Fe2O3 are formed. So 1700/2 = 850 kJ are released for 1 mole Fe2O3 formed. How many moles Fe2O3 do you have from 453 kJ? That will be 453/850 = ??
Convert that to grams. '
Check my thinking.

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