# Chemistry II

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What is the molarity of a solution in which 13.7 g of calcium chloride is dissolved in water to a final volume of 750.0 mL?

• Chemistry II -

Atomic weight of
Ca : 40
Cl : 35.5
Molecular weight of CaCl2=40+35.5*2=111
Moles=weight in grams/Molecular weight
=13.7/111 = 0.1234 moles
Molarity = 0.1234 moles/750 ml.
=0.165 moles/l
Please check the atomic weights and the calculations.

• Chemistry II -

Also note that units are missing and incorrect in places so that equations do not balance.

Relative Atomic Mass (RAM) of
Ca : 40
Cl : 35.5

Relative Molecular Mass of CaCl2=40+(35.5*2)=111

Moles=mass in grams/RAM

=13.7 g/111 g mol^-1
= 0.1234 mol

Molarity of solution = 0.1234 mol/0.7500 l.
=0.165 mol/l

or 0.165 M

• Chemistry II -

Thank you Dr. Russ.

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