Post a New Question

physics

posted by .

A circular steel wire 2.00 m is to stretch no more than 0.25 cm when a tensile force of 400 N is applied to each end of wire. What minimum diameter is required for the wire?

  • physics -

    area = pi d^2/4
    length = 2 m
    change in length = .0025 m

    change in length/length = .0025/2

    = tensile stress/E = 400/(pi d^2/4 E)
    so
    .00125 = 400/ (pi d^2/4 E)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question