# Differential Calculus

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Given that p=(2q^2-5)^2. when q=3, it is increased by 0.7%. find the appropriate percentage in p.

• Differential Calculus -

when q = 3, p = (2*9-5)^2 =169
dp/dq = 2 (2q^2-5)(4q)
when q = 3, dp/dq = 312
dq = .007*3 = .021
so dp = 312*.021 = 6.552
100 * dp/p = 100 *6.552/169 = 3.88 %

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