Differential Calculus
posted by matrix school 2 .
you have the expression for dp.
q=3, dq=.007*3
Now solve for dp and solve for P at q=3
percentage change in p then is dp/p divided by 100.
alright...
dp(2q^25)^2, dp/dq = 2(2q^25)
dp = 0.007x3 = 0.021
dp = (2(2(2)^25)^2 = (6)^2 = 36
36x0.021 = 0.756
(2(2)^25)^2 (3)^2 = 9
0.021/9 x 100 = 2.3%
pls correct me.

dp/dq = 2(2q^25)
no
if p = (2q^25)^2
then dp/dq = 1 (2q^25)^1 (4q)
because
d/dq (2q^2) = 4 q