math,
posted by chrissy .
how would i sove this problem?
x^6 + 3x^3 + 2 = 0

x^6+3x^3+2=0
It can also be written as:
(x^3)^2+3(x^3)+2=0...........(1)
Let a=(x^3), then we may rewrite equation (1) as:
a^2+3a+2=0
or,a^2+a+2a+2=0
or,a(a+1)+2(a+1)=0
or,(a+1)(a+2)=0
either,a=1 or,a=2
that is (x^3)=1 or (x^3)=2
Therefore, x=1 or x=cube root of 2
this is the solution to your equation.
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