Chemistry - General
posted by Sahar .
1. Consider a calorimeter into which 135g of water at 45.3 degrees Celsius is added. The initial temperature of the calorimeter was 23.8C and the equilibrium temperature of the water and the calorimeter is 39.6C. Assuming there is no heat loss to the surroundings, what is the heat capacity of the calorimeter in J/C?
Isn't qH2O + qcalorimeter = 0?
q H2O = mass x specific heat x delta T.
q calor = mass x specific heat x delta T.
note: mass x specific heat calorimeter = calorimeter constant.
q H2O = 135 x 4.184 x (39.5-45.3)
q calorimeter = constant x (23.8-39.6)