# Chem

posted by .

I did an experiment were I added some water and KHP into a beaker and phenophalene [sp?]. It was a titration lab. We slowly added calciuum hydroxide into the beaker and waited till the solution turned into a faint pink. The question is asking me to find the number of mols of calcium hydroxide used to neutralize the KHP. Can I just convert the number of mL of calcium hydroxide I used into grams. I was thinking that 1 mL = 1 gram. And then after just find the molar mass and divide.

• Chem -

You don't need to do that.
moles = M x L or
millimiles = M x mL.
Just remember that you probably will be asked for the moles KHP and to do that you must convert from moles Ca(OH)2 to moles KHP with the equation,
2KHP + Ca(OH)2 ==> 2H2O + CaK2P2
So obviously, moles KHP = 2 x moles Ca(OH)2

• Chem -

but M is in grams/mol.d When I said M I meant molar mass not molarity.

• Chem -

I repeat. If you want moles, it is M x L.
True, M is molarity and since M = moles/L, then M x L = moles.
I assume you have the molarity of the Ca(OH)2. And of course you may convert mL Ca(OH)2 to grams but chemicals react by moles and not grams. By the way, that CaK2P2 I wrote would better be written as K2P + CaP.

• Chem -

We weren't given the molarity of Ca(OH)2, that's why I don't understand how to do the question.

• Chem -

Were you given grams? Then grams/molar mass = moles Ca(OH)2. Then moles/L = M.
You don't have enough information so far to convert mL into grams. And you may not assume that 1 mL 1 gram unless that was the actual mass Ca(OH)2 used. You may have done the experiment to determine the molarity of the Ca(OH)2 in which case you would need the mass of the KHP used. If that's the case, mass KHP/molar mass KHP moles. Then 1/2 that is moles Ca(OH)2. Then M Ca(OH)2 = moles/L in the titration.

## Similar Questions

1. ### chemistry

Hi Cna someone please tell me what I must out into the Trial 1 column?
2. ### chemistry

Let me repost the important information only: Purpose: The purpose of this experiment is to determine the Ksp for calcium hydroxide. Materials are: *50.0 mL of 0.10 M HCl(aq) *bromophenol blue indicator *50.0 mLsaturated calcium hydroxide …
3. ### chemistry

Purpose: The purpose of this experiment is to determine the Ksp for calcium hydroxide. Materials are: *50.0 mL of 0.10 M HCl(aq) *bromophenol blue indicator *50.0 mLsaturated calcium hydroxide *50.0 mL buret *125 mL Erlynmyer Flask …
4. ### chemistry

You have four beakers labeled A, B, C, and D. In beaker A, you place 100 grams of silver nitrate and enough water to make 50 mL of solution. In beaker D, you place 100 grams of KCl and enough water to make 100 mL of solution. You also …
5. ### Chemistry

Two beakers were used in an experiment each with 100g of water at 30 degrees C. To the first beaker, 90g of NaNO3 was added. To the second beaker, 90g of KNO3 was added. (a)Which beaker had the salt precipitate out (settle to the bottom) …
6. ### chemistry

write the metal ion complex (predominant one) for the beakers: all four beakers contained .1M Ni(NO3)2 6H20, which was a light teal green to beaker 2, 1mL of 6MNH3 was added, and it turned bright blue to beaker 3 and 4, 1 mL of 30%en …
7. ### AP Chem

A student chemist named Hannah Montana set up an electrical conductivity tester similar to that shown on page 141 and conducted an experiment involving two clear, colorless liquids, identified as solution A and solution B. Solution …
8. ### chemistry

valerie placed 1.0g of salt into one beaker, 1.0g of soil into a second beaker, and 2.0g of sugar in a third beaker. She then added 200mL of water to each beaker and stirred the contents for 3 mintues. How many compounds and how many …
9. ### chemistry

A student is given 3 beakers: Beaker 1- 50.0 ml of a solution produced by dissolving 6.00 grams of a weak monoprotic acid ,HX, in enough water to produce 1 liter of solution. The empirical formula of HX is CH2O. The solution contains …
10. ### Science

I have 59.73 grams of a solid dissolved into water. The total is now 115ML of water. I added the water into a beaker already containing said solid. I did not measure how much water I put into the beaker. 59.73g/115ML=0.51g/ML My question …

More Similar Questions