Math
posted by jeff .
a parabola has vertex (6,12) AND PASSES THROUGH (6,24) find its equation in the form ax^2+bx+c

let the equation be in the form
y = a(xh)^2 + k, where (h,k) is the vertex
so we have
y = a(x+6)^2  12
plug in the point (6,24) to get a
24 = a(12)^2  12
a = 36/144 = 1/4
so y = (1/4)(x6)^2  12
expand this to change it into the required form
Please check my arithmetic, I am still on my first cup of coffee.
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