algebra
posted by Jessica .
Find b^2  4ac and the number of real solutions to equation.
3x^2+7x=0

The equation is in the form
ax^2 + bx + c = 0
3x^2 + 7x = 0
So, a = 3, b = 7, and c = 0
b^2  4ac = 49  0 = 49
The square root of a positive number is a real number, so there are 2 real solutions by the quadratic formula.
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