Algebra

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Use the quadratic formula to find the exact solutions of the equation. Show work. Simplify the final results as much as possible.

4x^2 – 16x + 25 = 0.

  • Algebra -

    The exact question was asked by Pamela yesterday. I have copied down my solution. For more information, view the entire thread.

    (a) The equation is in the form ax^2 + bx + c

    Use those values for b^2 - 4ac.

    (-16)^2 - 4*4*25
    = 256 - 400
    = -144

    The determinant is negative, so there will be two imaginary solutions.

    (b) The quadratic equation is x = (-b +/- sqrt(determinant))/(2a)

    Using the values of a, b, and c from the equation, we get

    x = (16 +/- sqrt(-144))/(2*4)
    x = (16 +/- 12i)/8
    x = 2 +/- 3i/2

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