Algebra
posted by Angie .
Solve the equation. Check all proposed solutions. Show work in solving and in checking.
Root3x = x1

sqrt(3x) = x1.
Start by squaring both sides.
3  x = x^2  2x + 1
0 = x^2  x  2
Factor the equation:
0 = (x2)(x+1)
So x = 2 or x = 1 
you made a mistake it is x=2 or x=1 its x=2 or x=1

I am still confused. Can someone please explain further and break this problem down cause I have 5 more like this one to do. Thank you!

from Marth's last line
So x = 2 or x = 1 ...
that should have said
So x = 2 or x = 1
Since he squared both sides, all answers must be verified.
if x=2
LS = √(32) = √1 = 1
RS = 21 = 1 OK
if x = 1
LS = √(3+1) = √4 = 2
RS = 1  1 = 2
so LS is not equal to RS
so the only solution is x = 2 
2 or 1 or
2 or 1?
annaiiz ceballos said
it is x=2 or x=1 its x=2 or x=1